Question 448012
What's the logarithmic form of? 
4^-2=1/6
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4^-2=1/6
This given equation is not correct. 4^-2=1/4^2=1/16
I will answer the question assuming the correct equation is 4^-2=1/16

What you see here is the exponential form of a logarithm, which in effect says: The base(4), raised to the logarithm of the number(-2), is equal to the number(1/16).
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So, in logarithm form:
logarithm of (1/16) to the base (4) is equal to -2
or log4(1/16)=-2