Question 448004
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Use the two-point form of an equation of a straight line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


Substitute your values, do the arithmetic, and then solve the equation for *[tex \Large y] in terms of everything else.  This means rearrange your equation so that *[tex \Large y] is all by itself in the LHS and everything else is in the RHS.  When you are done, your equation should have the form *[tex \Large y\ =\ mx\ +\ b] which is the slope-intercept form.


Note: It doesn't matter which of the points you decide is *[tex \Large P_1] and which you decide is *[tex \Large P_2] so long as you remain consistent throughout a given problem.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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