Question 447892
let a = apples and b = banana

then we have: 
1) (7*a) + (1*b) = $0.98 and,
2) (2*a) + (3*b) = $0.66

now from statement 1) let's re arrange and isolate b, we get that b = $0.98-(7*a)

now since the apples and bananas are the same things in both 1) and 2) we can take our rearrangement of b in 1) and replace it in the b for 2)

so we'll get, in 2), that (2*a) + (3*(0.98-7a)) = 0.66

you should be able to do the rest on your own, from the rearrangement in the second statement you only have one variable, the apples, collect like terms and solve for a. once you do that, plug the value of a in either 1) or 2) and solve for b, you'll get the same answer regardless of choosing 1) or 2)