Question 447700
solve for x; 9 to the x power = .75
{{{9^x}}} = .75
Using nat logs
{{{ln(9^x)}}} = ln(.75)
log equiv of exponents
x*ln(9) = ln(.75)
x = {{{ln(.75)/ln(9)}}}
x = -.131
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Check on a calc: enter 9^-.131, results .74988 ~.75