Question 46468
Actually, the formula is {{{pH = -log(10,x)}}}
pH = 9.3
{{{pH = -log(10,x)}}}
{{{9.3 = -log(10,x)}}}
{{{-9.3 = log(10,x)}}}
{{{10^(-9.3) = x}}}
{{{10^(-3/10) X 10^(-9) = x}}}
{{{(1/10^(3/10)) X 10^(-9) = x}}}
{{{(1/10^(3/10)) X 10^(-9) = x}}}
0.50119 X 10^(-9) = x
5.0119 X 10^(-10) = x Answer: D)