Question 447635
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First hit: *[tex \Large 9].


Second hit:  *[tex \Large \frac{2}{3}(9)\ =\ 6]


Third hit: *[tex \Large \frac{2}{3}\left(\frac{2}{3}\right)(9)\ =\ \frac{2}{3}(6)\ =\ 4]


Fourth hit: *[tex \Large \frac{2}{3}\left(\frac{2}{3}\right)\left(\frac{2}{3}\right)(9)\ =\ \frac{2}{3}\left(\frac{2}{3}\right)(6)\ =\ \frac{2}{3}(4)\ =\ \frac{8}{3}]


In general: *[tex \Large n]-th hit:  *[tex \Large \left(\frac{2}{3}\right)^{n\,-\,1}(9)]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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