Question 447205

Find the equation of a line containing the point (2,3) and perpendicular to the line 4x+3y=3


slope of given line = -4/3 , slope of line perpendicular to given line = 3/4

equation:   (y-3) = 3/4 (x-2)

=> 4y -12 = 3x - 6

=> 4y -3x = 6 



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Find the equation of the a line containing the points (3,4) and (4,8) 


(y-4) = (4-8)/(3-4) (x-3) 

=>  y-4 = 4(x-3)

=> y = 4x -12+ 4 

=> y = 4x -8