Question 447414
2x^2+x+2=57

2x^2+x-55=0

a=	2	b=	1	c=	-55		
							
b^2-4ac=	1+440				
b^2-4ac=	441
{{{sqrt(	441)}}}=	21
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}					
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(-1+21)/4		
x1=5						
x2=(-1-21)/4			
x2= -5.5						
Ignore negative value							
x	=	5	

5 &7	
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