Question 447344
<pre>
{{{y=2*root(3,8x-24)-1}}}

Factor what's under the radiucal:

{{{y=2*root(3,8(x-3))-1}}}

The cube root of 8 is 2 because 2³ = 2*2*2 = 8

Take the 8 out from under the cube root and
put its cube root, 2, in front of the radical:

{{{y=2*2*root(3,x-3)-1}}}

Then we nultiply the 2 by the 2 and get 4

{{{y=4*root(3,x-3)-1}}}

Edwin</pre>