Question 447300
Two cyclists leave town at the same time on the same road going in the same direction.
 Cyclist A is going 6 miles per hour faster than cyclist B.
 After 8 hours cyclist A has traveled three times the distance as cyclist B.
 How fast is cyclist B traveling?
:
Let s = speed of B cyclist
then
(s+6) = speed of A cyclist
:
Write a dist equation, Dist = time * speed
A's dist = 3 times B's dist
8(s+6) = 3(8s)
8s + 48 = 24s
48 = 24s - 8s
48 = 16s
s = 48/16
s = 3 mph is B's speed
:
:
Check by finding the actual dist each traveled
A: 9*8 = 72 mi
B: 3*8 = 24 mi