Question 447286
door length = 8 ft
width == 4 ft

Glass pan length = 8-2b
glass pane width = 4-2b

Total door area - Area of pane = Area of frame
32-(8-2b)(4-2b)= arae of the frame
32= 3(32-(8-2b)(4-2b))-1
33= 3(32-(32-24b+4b^2))
/3
11=(32-(32-24b+4b^2))
11=32-32+24b^2-4b^2
4b^2-24b+11=0
Find the roots of the equation by quadratic formula			
a=	4,	b=	-24,	c=	11	
Let the roots be x1.x2
						
b^2-4ac=576-176			
b^2-4ac=400
sqrt(400)=20
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}						
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}						
x1=(24+	20)/8	
x1=5.5					
x2=(24-20)/8		
x2=0.5				
Obviously the width will be 0.5 ft.

m.ananth@hotmail.ca