Question 447233
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There is a problem with the way you asked your question.  You cannot find "the" equation of a line.  The set of equations which graph to a given line is infinite, hence the best anyone can do is to derive <i>an</i> equation that is represented by a graph that is parallel to a line whose graph is a given equation and which passes through a given point.


In your case, the given equation is in slope-intercept form, namely *[tex \Large y\ =\ mx\ +\ b], so that the slope of the line represented by the given equation can be determined simply by inspection of the coefficient on the *[tex \Large x] term.


Parallel lines have identical slopes, hence an equation of a line parallel to the line represented by your original equation will have an identical coefficent on the *[tex \Large x] term.


Use the point-slope form of an equation of a line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the determined slope.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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