Question 446980
The legs in an isosceles right triangle measure 5 units more than twice the measure of the third side.
 Find the measure of each side of the triangle if the perimeter is 30.
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I don't think this can be a "right triangle"
:
Let x = the third side
then it say,"legs in an isosceles triangle measure 5 units more than twice the measure of the third side"
2x + 5 = legs of the isosceles triangle
:
The three sides = 30
2(2x+5) + x = 30
4x + 10 + x = 30
4x + x = 30 - 10
5x = 20
x = {{{20/5}}}
x = 4 units is the 3rd side
then
2(4) + 5 = 13 units are the other two sides
:
:
Check: 13+13+4 = 30