Question 447077
Let x ft be the width of the rectangle.
Let 3x-1 ft be the length of the rectangle.
...
l*w=A
(3x-1)(x)=30
3x^2-x=30
3x^2-x-30=0
*[invoke quadratic "x", 3, -1, -30 ]
x must be positive.
x=3.33
3x-1=9
Therefore, the rectangle is 3.33 ft by 9 ft.