Question 447019
Find A and B such that: 2x/(2x-3)(x+5)=A/(2x-3)+B/x+5
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lcd = (2x-3)(x+5)
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(2x+0)/lcd = [A(x+5)-B(2x-3)]/lcd
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Equate the numerators:
2x+0 = (A-2B)x+(5A+3B)
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Solve:
A-2B = 2
5A+3B=0
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Multiply 1st by 5:
5A-10B = 10
5A+3B = 0
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Subtract and solve for "B":
13B = -10
B = -10/13
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Solve for "A":
A - 2B = 2
A -2(-10/13) = 2
A + 20/13 = 26/13
A = 6/13
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Cheers,
Stan H.
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