Question 446858
Slope of Line Ac

x1		y1	x2	y2				
-1		-2	0	1				
								
slope m =(y2-y1)/(x2-x1)						
(1-(-2)/(0-1)
(3/1)  				
m=3		
Slope of line BD	

x1		y1	x2	y2				
-3		2	3	0				
								
slope m =(y2-y1)/(x2-x1)						
(0-2)/(	3-(-3)	) 
(-2/6)  				
m=-0.33		

m1*m2=-1
so the lines are perpendicular