Question 446614
Division of complex numbers is
{{{(a+bi)/(c+di)=((ac+bd)/(c^2+d^2))+((bc-ad)/(c^2+d^2))i}}}
if you need more info or proof search complex numbers on Wikipedia.
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{{{(3+2i)/(2+i)}}}
={{{((3*2+2)/(4+1))+((4-3)/(4+1))*i}}}
={{{(8/5)+(1/5)i}}}