Question 446815
Using the Pythagorean theorem works well. If you can intuit the problem, recognize the 6-8-10 right triangle and note that 2(6+8) = 28, that works even better.


If you were to use the Pythagorean theorem, then you could say that


*[tex \LARGE \sqrt{x^2 + y^2} = 10 \Rightarrow x^2 + y^2 = 100] given the constraint that x+y = 14. Then, you could say that y = 14-x, replace to obtain the equation


*[tex \LARGE x^2 + (14-x)^2 = 100]


Then solve for x and y.