<PRE><B>Question 446736</B>
a(T)=-2t(squared)+32T+12
the amount of nitrogen dioxide A was present in the air. T is the number of hours after 6 am. Use this function to find the time at which the nitrogen dioxide level was at its maximum. Graph the parabola.
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a(T) = -2T^2+32T+12
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Quadratic with a = -2 ; b = 32
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Max occurs when T = -b/(2a) = -32/(2*-2) = 8 hrs
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Time at max nitrogen dioxide level 6am + 8 hr = 2pm
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Cheers,
Stan H.</PRE>