Question 446717
Let x be the first integer.
Let x+1 be the second integer.
Let x+2 be the third integer.
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(x)(x+1)=x+2+62
x^2+x=x+2+62
x^2+x-x-64=0
x^2-64=0
x^2-(8)^2=0
(x+8)(x-8)=0
x=-8 or x=8
x+2= -6 or 10
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x=10 as that is the the forth choice d.