Question 446703
Find the amount of the 10% and 20% solution if he mixes to get 20 liters of 18% saline solution?
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Assume the active ingredient is "ai"
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Equation:
ai + ai = ai
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0.10x + 0.20(20-x) = 0.18*20
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Multiply by 100:
10x + 20*20-20x = 18*20
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-10x = -2*20
x = 4 liters (amt of 10% solution needed)
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20-x = 16 liters (amt of 20% solution needed)
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Cheers,
Stan H.