Question 446557
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Hi
 {{{sqrt(3x+1) + 3 = x}}}
 {{{sqrt(3x+1) = x-3 }}}
 {{{ 3x+1 = (x-3)(x-3) }}}
    3x+1 = x^2 - 6x + 9
    x^2 - 9x+ 8 = 0
factoring
 (x-1)(x-8) = 0
 (x-1)= 0  x = 1 an Extraneous solution:  2 + 3 &#8800; 1
 (x-8) = 0 x = 8