Question 446494
 
Company A charges $55 per day plus $0.35 per mile to rent a car.
A(x) = 55x + 0.35m
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Company B charges $50 per day plus $0.40 per mile. 
B(x) = 50x + 0.40m
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Jack wants to rent a car for three days.
Solve:
(55*3+0.35m) < (50*3+0.40m)
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5*3 < 0.05m
m > 15/0.05
m > 300 miles
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Cheers,
Stan H.  

How many miles should Jack be traveling so that Company A is less expensive than Company B?