Question 446477
Solve the equation:{{{x^2+(x+1)^2=85}}}. Set the equation to zero:

{{{2x^2+2x-84=0}}}=>{{{x^2+x-42=0}}}=>{{{(x-6)(x+7)=0}}}

The solution is: x=-7 which is rejected because it is not natural number, and

x=6 which is the right solution.

Answer:Two consecutive natural numbers are 6 and 7.