Question 446475
Well you can't really solve them but, you mean factor right?
...
First of all you can use the identity {{{a^3-b^3=(a-b)(a^2+ab+b^2)}}}
...
1){{{y^3-64}}}
={{{(y)^3-(4)^3}}}
={{{(y-4)(y^2+4y+16)}}}
...
2){{{1000x^3-27}}}
={{{(10x)^3-(3)^3}}}
={{{(10x-3)(100x^2+30x+9)}}}