Question 446465
x1	y1	x2	y2										
d= 	{{{sqrt((y2-y1)^2+(x2-x1)^2)}}}												
6	1	6	7										
d(AB)= {{{sqrt((7-1)^2+(6-6)^2)}}}
d= {{{sqrt((6)^2	+(0)^2)}}}				
d= {{{sqrt((36))}}}								
d(AB)= 	6.00										
x1	y1	x2	y2										
d(BC)= 	{{{sqrt((y2-y1)^2+(x2-x1)^2)}}}												
10	7	6	7										
d= {{{sqrt((7-7)^2+(6-10)^2)}}}
d={{{sqrt((0)^2+(-4)^2)}}}				
d= {{{sqrt((16))}}}								
d(BC)= 	4.00
----											
x1	y1	x2	y2										
d(CA)= 	{{{sqrt((y2-y1)^2+(x2-x1)^2)}}}												
10	7	6	1										
d= {{{sqrt((1-7)^2+(6-10)^2)}}}
d= {{{sqrt((-6)^2+(-4)^2)}}}				
d= {{{sqrt((52))}}}								
d(CA)= 	7.215												
	
d(AB)^2+d(BC)^2= d(AC)^2 if it is a right triangle		
6^2+4^2= 7.215^2
52=52