Question 446117
An arrow is fired into the air with an initial velocity of 64 feet per second. The height in feet of the arrow after t seconds after it was shot into the air is given by the function h(x)=-16t(squared) +64t. Find the maximum height of the arrow.
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h(x)=-16t(squared) +64t.
y=-16t^2+64t
Change equation into standard form for parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex.
completing the square
y=-16(t^2-4t+4)+64
y=-16(t-2)^2+64
vertex(2,64)
ans:
The arrow will reach its maximum height of 64 feet 2 seconds after it was shot into the air.