Question 446283
Let x cm be the shortest side.
Let x+2 cm be the other leg.
Let x+4 cm be the hypotenuse of the triangle.
...
{{{x^2+(x+2)^2=(x+4)^2}}}
{{{x^2+x^2+4x+4=x^2+8x+16}}}
{{{2x^2-x^2+4x-8x+4-16=0}}}
{{{x^2-4x-12=0}}}
*[invoke quadratic "x", 1, -4, -12 ]
The answer has to be positive so
x=6
x+2=8
x+4=10
Therefore, the dimensions of the triangle is 6cm by 8cm by 10cm.