Question 446283
The hypotenuse of a right triangle is 4 cm longer than the shortest side and 2 cm longer than the remaining side. Find the dimensions of the triangle.

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Let shortest side be "x".
The hypotenuse = "x+4"
And 3rd side is "x-2".
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Equation:
x^2 + (x-2)^2 = (x+4)^2
x^2 + x^2-4x+4 = x^2+4x+16
x^2-8x-12 = 0
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(x-6)(x-2) = 0
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x = 6 or x = 2
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Cheers,
Stan H.
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