Question 446265
Let x be the smaller number.
Let x+2 be the next consecutive odd number.
...
{{{x^2+(x+2)^2=3*x^2-1}}}
{{{x^2+x^2+4x+4=3x^2-1}}}
{{{0=3x^2-2x^2-4x-4-1}}}
{{{x^2-4x-5=0}}}
*[invoke quadratic "x", 1, -4, -5 ]
x=-1 or x=5
x+2=1 or x+2=7
Therefore, the two integers are -1 and 1 or they are 5 and 7.