Question 46346
{{{sqrt(x - 1) = x - 3}}}
{{{x - 1 = x^2 - 6x + 9}}}
{{{0 = x^2 - 7x + 10}}}
{{{0 = (x - 5)(x - 2)}}}
x = 5
and
x = 2
Check:
{{{sqrt(x - 1) = x - 3}}}
{{{sqrt(5 - 1) = 5 - 3}}} correct
and
{{{sqrt(x - 1) = x - 3}}}
{{{sqrt(2 - 1) = 2 - 3}}} incorrect