Question 446170
given:
{{{ c = 3d }}}
{{{ b = 2d }}}
{{{ b + c + d = 192 }}}
By substitution:
{{{ 2d + 3d + d = 192 }}}
{{{ 6d = 192 }}}
{{{ d = 32 }}}
and
{{{c  = 3d}}}
{{{ c = 3*32 }}}
{{{ c = 96 }}}
and
{{{b = 2d }}}
{{{ b = 2*32 }}}
{{{ b = 64 }}}
Bench has 64, Collins has 96, Delorey has 32
check:
{{{ b + c + d = 192 }}}
{{{ 64 + 96 + 32 = 192 }}}
{{{ 192 = 192 }}}