Question 446017
 {{{f(x) = (2 / x^2) - 1}}}

 {{{f(x) = (2- x^2/ x^2) }}}

 {{{f(x) = -( x^2-2/ x^2)}}}


Lim (x tend to -1 ) [-( x^2-2/ x^2)]=-1

 domain is R - {-1,1} as at a these points its is not defined

taking limit at (-1). Lim (x tend to -1 ) [2 / x^2 - 1] applying L -hospital we get limit as 0 

similar for 1

for x from -1 to 1:

{{{ graph( 500, 500, -1, 1, -10, 20,-( x^2-2/ x^2)) }}}


for x from -6 to 6:

{{{ graph( 500, 500, -6,6, -10, 20,(2- x^2)/ x^2) }}}