Question 445924
First we find the slope of the line which passes through the (8, -2) and 
center of the circle (3,-2). This line contains the radius and is perpendicular to the tangent line at (8, -2).

The slope is:{{{m=(-2+2)/(8-3)=0}}}, since its slope is zero the line is parallel 

to the x-axis, and its equation is: y=-2. The equation of the tangent line at

 (8, -2) will be: x=8.

Answer:The equation of the line is x=8.