Question 445878
Let {{{a}}} = number of 1-point shots she made
Let {{{b}}} = number of 2-point shots she made
Let {{{c}}} = number of 3-point shots she made
given:
(1) {{{ a + b + c = 356 }}}
(2) {{{ b = a + 76 }}}
(3) {{{ a = c + 77 }}}
This is 3 equations with 3 unknowns, so it's solvable
(3) {{{ a = c + 77 }}}
(3) {{{ c = a - 77 }}}
Substitute (2) and (3) in (1)
(1) {{{ a + b + c = 356 }}}
(1) {{{ a + a + 76 + a - 77 = 356 }}}
(1) {{{ 3a - 1 = 356 }}}
(1) {{{ 3a = 357 }}}
{{{ a = 119 }}}
and
(2) {{{ b = a + 76 }}}
(2) {{{ b = 119 + 76 }}}
{{{ b = 195 }}}
and
(3) {{{ c = 119 - 77 }}}
{{{ c = 42 }}}
She made 119 1-point shots 
She made 195 2-point shots 
She made 42 3-point shots