Question 445854
log (2x + 2) – log (x + 5) =0
log (2x + 2)/(x + 5) =0
(2x + 2)/(x + 5) =10^0
(2x + 2)/(x + 5) =1
(2x + 2)=(x + 5)
x + 2 = 5
x = 3