Question 445087
To multiply these first you'll have to change them to the same base.  You can convert these all to base 2.
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{{{4^x*16^(3x-1)=8}}} 
{{{(2^2)^x*(2^4)^(3x-1)=2^3}}}
{{{2^(2x)*2^(4(3x-1))=2^3}}}
{{{2^(2x)*2^(12x-4)=2^3}}}
{{{2^((2x)+(12x-4))=2^3}}}
{{{2^(14x-4)=2^3}}}
therefore,{{{14x-4=3}}}
since if, {{{2^(junk)=2^(garbage)}}}
therefore, {{{junk=garbage}}}
so,{{{14x-4=3}}}
{{{14x=3+4}}}
{{{14x=7}}}
{{{x=7/14}}}
{{{x=1/2}}}
Therefore, x=1/2.