Question 445111
Let x m be the width of the parking lot.
Let 2x-10 m be the length of the parking lot.
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P=2(l+w)
412=2(2x-10+x)
412=2(3x-10)
412=6x-20
6x=412+20
6x=432
x=432/6
x=72
2x-10=134
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Therefore, the length of the parking lot is 134 m.