Question 445044
y^2+8y+32=0
{{{y = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
y=(-8+-sqrt[8^2-4*1*32])/2*1
y=(-8+-sqrt[64-128])/2
y=(-8+-sqrt[-64]/2
y=(-8+-8i)/2
y=-8/2+81/2
y=-4+41 ans.
y=(-8-8i)/2
y=-8/2-81/2
y=-4-4i* ans.