Question 444912
You have four 1$ bills, two 5$ bills, and one 20$ bill in your wallett. You choose one of the bills at random. Find the odds in favor of and the odds against of choosing a bill greater then 1$.
<pre><font face = "consolas" color = "indigo" size = 2><b>

You have these 7 bills:

<font color = "green">$1</font>, <font color = "green">$1</font>, <font color = "green">$1</font>, <font color = "green">$1</font>, <font color = "red">$5</font>, <font color = "red">$5</font>, <font color = "red">$20</font>


Those 3 which I have colored red are favorable and the
other 4 which I have colored green are not favorable.

So the odds in favor are

(Number of favorable possibilities) : (number of non-favorable possibilities)

So that's 3 favorable ones to 4 unfavorable ones, which is written

3:4

The odds against is just the reverse 

(Number of unfavorable possibilities) : (number of favorable possibilities)

So that's 4 unfavorable ones to 3 favorable ones, which is written

4:3

Edwin</pre>