Question 444456
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Hi, Previously Posted
Standard Form of an Equation of an Hyperbola opening up and down is:
  {{{(y-k)^2/b^2 - (x-h)^2/a^2 = 1}}} 
where Pt(h,k) is a center  with vertices 'b' units up and down from center.
vertices: (1,-8), (1,-2)  b = 6/2= 3 then Center is (1,-5) 
  {{{(y+5)^2/9 - (x-1)^2/a^2 = 1}}}
 foci: (1,-10),(1,0) {{{sqrt( 9 + a^2) = 10/2 = 5}}} a^2 = 16
   {{{(y+5)^2/9 - (x-1)^2/16 = 1}}}
  {{{drawing(300,300,-20,20,-20,20,grid(1),
circle(1, -5,0.4),
circle(1, -8,0.4),
circle(1, -2,0.5),
graph( 300, 300, -20,20,-20,20,0,3sqrt(1+ (1/16)(x-1)^2)-5,-3sqrt(1+ (1/16)(x-1)^2)-5 ))}}}