Question 444861

{{{x^3 + 4x^2 - 45x > 0  }}}

{{{x(x^2 + 4x - 45) > 0  }}}...so, one solution is {{{x>0}}}

factor {{{(x^2 + 4x - 45) > 0  }}}

{{{(x^2-5x + 9x - 45) > 0  }}}

{{{((x^2-5x )+ (9x - 45)) > 0  }}}

{{{x(x-5) + 9(x - 5) > 0  }}}

{{{(x+ 9)(x - 5) > 0  }}}......the other two solutions are:

{{{x+ 9> 0  }}}...=>...{{{x>-9}}}

and

{{{x-5> 0  }}}...=>...{{{x>5}}}

so, your answer is:

B. (-9, 0) or (5, ∞) ........here is graph above {{{x-axis}}}