Question 444432
A random sample of 42 graduates revealed worked 5.5 yrs 
the sample standard deviation was 1.1 yrs 
Using 99% degree of confidence, what is the confidence interval for the population mean.
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x-bar = 5.5 
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ME = zs/sqrt(n) = 2.5758*1.1/sqrt(42) = 0.4372
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99% CI: 5.5-0.4372 < u < 5.5+0.4372
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Cheers,
Stan H.
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