Question 444475
If you roll a standard number cube twice. 
Comment: These roll results are all independent.
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Find each probability. 
P(1, then 2) = (1/6)(1/6) = 1/36
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P(3, then even) = (1/6)(1/2) = 1/12
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P(less than 4, then 1) = (3/6)(1/6) = 1/12
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P(odd, then even) = (3/6)(3/6) = 1/4
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P(divisible by 2, then 5) = (3/6)(1/6) = 1/12
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P(greater than 2, then odd) = (4/6)(1/6) = 1/9
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Cheers,
Stan H.
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