Question 444436
 <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi
ln x- ln(x-1)= 2
ln (x/(x-1) = 2
  e^2 = x/(x-1)
 7.389 = x/(x-1)
 7.389(x-1) = x
  6.389x = 7.389
       x = 1.1565

*[tex \large \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]