Question 444242
I am not sure how to resolved this math problem: 
Find points of intersection for
2x-4y>6
3x+2y<6 
(Solve by graphing and state 1 solution and 1 non-solution) 
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1st: Graph the boundary line of the 1st inequality:
y = 2x/4-6/4
y = (1/2)x-(3/2)
2nd: Sketch that boundary as a dashed line.
3rd: Since you want y < (1/2)x-(3/2), shade the
half-plane BELOW the boundary.
{{{graph(400,300,-10,10,-10,10,y<(1/2)x-(3/2))}}}
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1st: Graph the boundary line of the 2nd inequality:
y =(-3/2)x +3
2nd: Sketch that as a dashed line.
3rd: Since you wan y < (-3/2)x+3, shade the 
half-plane BELOW the boundary.
{{{graph(400,300,-10,10,-10,10,y<(-3/2)x + 3)}}}
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A point IN the intersection: (0,0)
A point Not IN the intersection: (0,6)
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Cheers,
Stan H.