Question 444211
simplfy each complex fraction.. can you help ?


2/x 
______   =?

1- 1/y
------------------------------
(2/x)/[1-(1/y)]
---
= (2/x)/[(y-1)/y]
---
Invert the denominator and multiply to get:
= (2/x)(y/(y-1)
---
= (2y)/(xy-x)
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2.    3-3/x
     --------
      1/2 - 1/x
--------------------
(3-(3/x))/[(1/2)-(1/x)]
----
[(3x-3)/x] / [(x-2)/(2x)]
----
Invert and multiply:
---
[(3x-3)/x]*[(x-2)/(2x)]
---
= [3(x-1)(x-2)]/[2x^2]
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Cheers,
Stan H.
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