Question 444198
Based on the exponents properties we get:

{{{(3^(2n+1)*6^n)/(2^(n-1)*3^(3n)) = 3^(2n+1)*3^n*2^n*2^(1-n)*3^(-3n)}}}=

 ={{{3^(2n+1+n-3n)*2^(n+1-n)=3^1*2^1=3*2=6}}}