Question 46159
Let's see.
Solve:
{{{5x = -4x^2-2}}} Rewrite in standard form.
{{{4x^2+5x+2 = 0}}} You are correct in using the quadratic formula because this does not factor. Here, a = 4, b = 5, and c = 2

{{{x=(-5+-sqrt(5^2-4(4)(2)))/2(4)}}}
{{{x=(-5+-sqrt(25-32))/8}}}
{{{x=(-5+-sqrt(-7))/8}}}

The roots are:

{{{x = -5/8+(sqrt(7)i)/8}}}
{{{x = -5/8-(sqrt(7)i)/8}}}