Question 444103
{{{root(3,60)}}} = about 4, the center
--> 3, 4 & 5
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The hard way:
x(x+1)(x+2) = 60
{{{x^3 + 3x^2 + 2x - 60 = 0}}}
Since the root of 3 is known:
x = 3
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If you didn't know the roots, you'd have to look at the factors of 60 and find the roots.